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[原创]TheBigMan's CrackMe #6算法分析
2009-2-3 22:31 6361

[原创]TheBigMan's CrackMe #6算法分析

2009-2-3 22:31
6361
【文章标题】: TheBigMan's CrackMe #6算法分析
【文章作者】: creantan
【作者邮箱】: creantan@126.com
【作者主页】: www.crack-me.com
【下载地址】: 附件
【作者声明】: 只是感兴趣,没有其他目的。失误之处敬请诸位大侠赐教!
--------------------------------------------------------------------------------
【详细过程】
  PEID查壳->ASPack 2.x (without poly) -> Alexey Solodovnikov [Overlay]
  脱之
  瞎输一个假码试运行,点Check没反应。。。。
  下断bp GetDlgItemTextA...
  断下返回
  找到关键点
  第一部分:
  00401528  |.  68 00010000   push    100                              ; /Count = 100 (256.)
  0040152D  |.  8D85 00FFFFFF lea     eax, dword ptr [ebp-100]         ; |
  00401533  |.  50            push    eax                              ; |Buffer
  00401534  |.  6A 65         push    65                               ; |ControlID = 65 (101.)
  00401536  |.  FF75 08       push    dword ptr [ebp+8]                ; |hWnd = 001C0B98 ('TheBigMan's CrackMe #6',class='#32770')
  00401539  |.  E8 FA010000   call    <jmp.&USER32.GetDlgItemTextA>    ; \GetDlgItemTextA
  0040153E  |.  89C3          mov     ebx, eax                         ;  取用户名,eax保存用户名长度
  00401540  |.  09DB          or      ebx, ebx
  00401542  |.  75 04         jnz     short 00401548                   ;  判断用户名是否为空
  00401544  |.  31C0          xor     eax, eax
  00401546  |.  EB 50         jmp     short 00401598
  00401548  |>  BF BC020000   mov     edi, 2BC
  0040154D  |.  BE 30000000   mov     esi, 30
  00401552  |.  B8 48000000   mov     eax, 48
  00401557  |.  99            cdq
  00401558  |.  F7FB          idiv    ebx
  0040155A  |.  29C6          sub     esi, eax
  0040155C  |.  8D34B6        lea     esi, dword ptr [esi+esi*4]
  0040155F  |.  29F7          sub     edi, esi
  00401561  |.  6BFF 6B       imul    edi, edi, 6B
  00401564  |.  81EF 6CCF0000 sub     edi, 0CF6C
  0040156A  |.  81FF 00230000 cmp     edi, 2300                        ;  checkLen = (0x2BC - (0x30 - 0x48 / nameLen) * 5) * 0x6B - 0x0CF6C;
  00401570  |.  7F 08         jg      short 0040157A                   ;  用户名长度检验
  00401572  |.  81FF 90010000 cmp     edi, 190
  00401578  |.  7D 04         jge     short 0040157E
  0040157A  |>  31C0          xor     eax, eax
  0040157C  |.  EB 1A         jmp     short 00401598
  0040157E  |>  8D85 00FFFFFF lea     eax, dword ptr [ebp-100]
  00401584  |.  50            push    eax                              ;  用户名
  00401585  |.  53            push    ebx                              ;  用户名长度
  00401586  |.  FF75 08       push    dword ptr [ebp+8]
  00401589  |.  E8 77FDFFFF   call    00401305                         ;  关键CALL
  

  F7进入算法第二部分:
  0040139E  |.  68 00010000   push    100                              ; /Count = 100 (256.)
  004013A3  |.  8D85 E1FCFFFF lea     eax, dword ptr [ebp-31F]         ; |
  004013A9  |.  50            push    eax                              ; |Buffer
  004013AA  |.  6A 66         push    66                               ; |ControlID = 66 (102.)
  004013AC  |.  FF75 08       push    dword ptr [ebp+8]                ; |hWnd
  004013AF  |.  E8 84030000   call    <jmp.&USER32.GetDlgItemTextA>    ; \GetDlgItemTextA
  004013B4  |.  09C0          or      eax, eax
  004013B6  |.  0F84 48010000 je      00401504                         ;  判断假码是否为空
  004013BC  |.  B8 CF110000   mov     eax, 11CF
  004013C1  |.  0FB68D E1FCFF>movzx   ecx, byte ptr [ebp-31F]          ;  假码第一个字符
  004013C8  |.  99            cdq
  004013C9  |.  F7F9          idiv    ecx
  004013CB  |.  83FA 17       cmp     edx, 17                          ;  模7余数与0x17比较
  004013CE  |.  74 07         je      short 004013D7                   ;  不等则不成功
  004013D0  |.  31C0          xor     eax, eax                         ;  可以计算下,不过后面有提示
  004013D2  |.  E9 2D010000   jmp     00401504
  004013D7  |>  31DB          xor     ebx, ebx
  004013D9  |.  EB 0B         jmp     short 004013E6
  004013DB  |>  8B45 10       /mov     eax, dword ptr [ebp+10]         ;  //////////////////////////
  004013DE  |.  0FBE0418      |movsx   eax, byte ptr [eax+ebx]
  004013E2  |.  0145 FC       |add     dword ptr [ebp-4], eax          ;  取用户名ASCII码总和
  004013E5  |.  43            |inc     ebx
  004013E6  |>  3B5D 0C        cmp     ebx, dword ptr [ebp+C]
  004013E9  |.^ 7C F0         \jl      short 004013DB                  ;  //////////////////////////
  004013EB  |.  31DB          xor     ebx, ebx                         ;  ebx为计数器先清零
  004013ED  |.  E9 83000000   jmp     00401475
  004013F2  |>  8B55 10       /mov     edx, dword ptr [ebp+10]         ;  用户名地址
  004013F5  |.  0FBE3C1A      |movsx   edi, byte ptr [edx+ebx]         ;  逐个取用户名字符
  004013F9  |.  8B75 FC       |mov     esi, dword ptr [ebp-4]          ;  用户名ASCII码总和
  004013FC  |.  89D9          |mov     ecx, ebx
  004013FE  |.  C1E1 02       |shl     ecx, 2
  00401401  |.  89DA          |mov     edx, ebx
  00401403  |.  42            |inc     edx
  00401404  |.  29D1          |sub     ecx, edx
  00401406  |.  0FB68C0D E1FE>|movzx   ecx, byte ptr [ebp+ecx-11F]
  0040140E  |.  89FA          |mov     edx, edi
  00401410  |.  31CA          |xor     edx, ecx
  00401412  |.  89F1          |mov     ecx, esi
  00401414  |.  0FAFCB        |imul    ecx, ebx
  00401417  |.  29F1          |sub     ecx, esi
  00401419  |.  89CE          |mov     esi, ecx
  0040141B  |.  83F6 FF       |xor     esi, FFFFFFFF
  0040141E  |.  8DB432 4D0100>|lea     esi, dword ptr [edx+esi+14D]    ;  edx+0x34b+0x14d
  00401425  |.  8B4D 0C       |mov     ecx, dword ptr [ebp+C]          ;  用户名长度
  00401428  |.  89DA          |mov     edx, ebx
  0040142A  |.  83C2 03       |add     edx, 3
  0040142D  |.  0FAFCA        |imul    ecx, edx
  00401430  |.  0FAFCF        |imul    ecx, edi
  00401433  |.  89F0          |mov     eax, esi
  00401435  |.  01C8          |add     eax, ecx
  00401437  |.  B9 0A000000   |mov     ecx, 0A
  0040143C  |.  31D2          |xor     edx, edx                         ;一堆加减乘除
  0040143E  |.  F7F1          |div     ecx
  00401440  |.  83C2 30       |add     edx, 30
  00401443  |.  88941D FCFEFF>|mov     byte ptr [ebp+ebx-104], dl
  0040144A  |.  0FB6BC1D FCFE>|movzx   edi, byte ptr [ebp+ebx-104]
  00401452  |.  81F7 ACAD0000 |xor     edi, 0ADAC
  00401458  |.  89DE          |mov     esi, ebx
  0040145A  |.  83C6 02       |add     esi, 2
  0040145D  |.  89F8          |mov     eax, edi
  0040145F  |.  0FAFC6        |imul    eax, esi
  00401462  |.  B9 0A000000   |mov     ecx, 0A
  00401467  |.  99            |cdq
  00401468  |.  F7F9          |idiv    ecx
  0040146A  |.  83C2 30       |add     edx, 30
  0040146D  |.  88941D FCFEFF>|mov     byte ptr [ebp+ebx-104], dl      ;  运算结果保存
  00401474  |.  43            |inc     ebx
  00401475  |>  3B5D 0C        cmp     ebx, dword ptr [ebp+C]          ;  ebx与用户名长度比较,用户名长度就是循环次数
  00401478  |.^ 0F8C 74FFFFFF \jl      004013F2
  0040147E  |.  8D85 FCFEFFFF lea     eax, dword ptr [ebp-104]         ;  结果地址给EAX
  00401484  |.  50            push    eax
  00401485  |.  6A 54         push    54                               ;  0X54 = 'T'
  00401487  |.  8D85 DCFBFFFF lea     eax, dword ptr [ebp-424]
  0040148D  |.  50            push    eax                              ; |Format
  0040148E  |.  8D85 E1FBFFFF lea     eax, dword ptr [ebp-41F]         ; |
  00401494  |.  50            push    eax                              ; |s
  00401495  |.  E8 CE020000   call    <jmp.&USER32.wsprintfA>          ; \wsprintfA
  0040149A  |.  8B7D 0C       mov     edi, dword ptr [ebp+C]           ;  格式化与‘T’连接
  0040149D  |.  89F8          mov     eax, edi
  0040149F  |.  0FAF45 FC     imul    eax, dword ptr [ebp-4]           ;  用户名ASCII长度和
  004014A3  |.  B9 64000000   mov     ecx, 64
  004014A8  |.  99            cdq
  004014A9  |.  F7F9          idiv    ecx
  004014AB  |.  89D7          mov     edi, edx
  004014AD  |.  83C7 30       add     edi, 30
  004014B0  |.  57            push    edi                              ;  (nameSum * nameLen) % 0x64 + 0x30
  004014B1  |.  8DBD E1FBFFFF lea     edi, dword ptr [ebp-41F]
  004014B7  |.  57            push    edi
  004014B8  |.  8DBD D6FBFFFF lea     edi, dword ptr [ebp-42A]         ;  (ASCII "%s-%d")这种形式格式化
  004014BE  |.  57            push    edi                              ; |Format
  004014BF  |.  8DBD E1FDFFFF lea     edi, dword ptr [ebp-21F]         ; |
  004014C5  |.  57            push    edi                              ; |s
  004014C6  |.  E8 9D020000   call    <jmp.&USER32.wsprintfA>          ; \wsprintfA
  004014CB  |.  83C4 20       add     esp, 20
  004014CE  |.  8D8D E1FDFFFF lea     ecx, dword ptr [ebp-21F]
  004014D4  |.  83C8 FF       or      eax, FFFFFFFF
  004014D7  |>  40            /inc     eax
  004014D8  |.  803C01 00     |cmp     byte ptr [ecx+eax], 0
  004014DC  |.^ 75 F9         \jnz     short 004014D7                  ;  计算格式化后的字符串长度
  004014DE  |.  50            push    eax                              ;  长度
  004014DF  |.  8D85 E1FCFFFF lea     eax, dword ptr [ebp-31F]
  004014E5  |.  50            push    eax                              ;  假码
  004014E6  |.  8D85 E1FDFFFF lea     eax, dword ptr [ebp-21F]
  004014EC  |.  50            push    eax                              ;  得到的字符串
  004014ED  |.  E8 D0FDFFFF   call    004012C2                         ;  关键CALL
  

  F7进入算法第三部分:
  004012CB  |.  31F6          xor     esi, esi                         ;  esi计数
  004012CD  |.  46            inc     esi                              ;  esi初始为1
  004012CE  |.  EB 29         jmp     short 004012F9
  004012D0  |>  8B55 08       /mov     edx, dword ptr [ebp+8]          ;  得到的字符串
  004012D3  |.  0FBE3C32      |movsx   edi, byte ptr [edx+esi]         ;  取第二位字符part[1]
  004012D7  |.  89F8          |mov     eax, edi
  004012D9  |.  83F0 20       |xor     eax, 20                         ;  eax ^= 0x20
  004012DC  |.  B9 0A000000   |mov     ecx, 0A                         ;  ecx = 0x0A
  004012E1  |.  99            |cdq
  004012E2  |.  F7F9          |idiv    ecx
  004012E4  |.  89D7          |mov     edi, edx                        ;  edx = eax % ecx;edi=edx
  004012E6  |.  83C7 30       |add     edi, 30                         ;  edi += 0x30
  004012E9  |.  8B55 0C       |mov     edx, dword ptr [ebp+C]
  004012EC  |.  0FBE1432      |movsx   edx, byte ptr [edx+esi]         ;  取假码对应位置的字符
  004012F0  |.  39D7          |cmp     edi, edx                        ;  与假码对应位字符比较
  004012F2  |.  74 04         |je      short 004012F8
  004012F4  |.  31C0          |xor     eax, eax                        ;  不等EAX置0然后return
  004012F6  |.  EB 08         |jmp     short 00401300
  004012F8  |>  46            |inc     esi
  004012F9  |>  39DE           cmp     esi, ebx
  004012FB  |.^ 7C D3         \jl      short 004012D0
  

  好了,算法到这结束了。。。
  
  注册机
  	int nameLen,nameSum = 0;
  	char name[255];
  	const char table[] = "ABCDEFGHIJKLMNOPQRSTUVWSYZ";
  	int i,checkLen;
  	printf("请输入用户名:");
  	scanf("%s",name);
  	nameLen = strlen(name);
  	checkLen = (0x2BC - (0x30 - 0x48 / nameLen) * 5) * 0x6B - 0x0CF6C;
  	if(checkLen <= 0x2300)
  	{
  		if(checkLen >= 0x190)
  		{
  			for(i = 0 ; i<nameLen ; i++)
  			{
  				nameSum += (int)name[i];
  			}
  			int esi = 0,edi = 0,ecx = 0,eax = 0;
  			byte edx = 0;
  			char serial[20],part[20];
  			for( i = 0 ; i < nameLen ; i++)
  			{
  				edi = (int)name[i];
  				esi = nameSum;
  				ecx = i;
  				ecx = ecx << 2;
  				edx = i;
  				edx++;
  				ecx -= edx;
  				if(ecx < 0)
  				{
  					ecx = 0;
  				}
  				else
  				{
  					ecx = table[ecx];
  				}
  				edx = edi;
  				edx ^= ecx;
  				ecx = esi;
  				ecx *= i;
  				ecx -= esi;
  				esi = ecx;
  				esi ^=0xffffffff;
  				esi = edx + esi +0x14D;
  				ecx = nameLen;
  				edx = i;
  				edx += 3;
  				ecx *= edx;
  				ecx *= edi;
  				eax = esi;
  				eax += ecx;
  				ecx = 0x0A;
  				edx = 0;
  				edx = eax % ecx;
  				edx += 0x30;
  				edi = edx;
  				edi ^= 0x0ADAC;
  				esi = i;
  				esi += 2;
  				eax = edi;
  				eax *= esi;
  				ecx = 0x0A;
  				edx = eax % ecx;
  				edx += 0x30;
  				part[i] = edx;
  			}
  			part[nameLen] = '\0';
  			int p;
  			p = (nameSum * nameLen) % 0x64 + 0x30;
  			wsprintf(serial,"%c%s-%d",0x54,part,p);
  			for(i = 1 ;i<13 ;i++)
  			{
  				serial[i]= ((serial[i] ^ 0x20) % 0x0A) +0x30;
  			}
  			serial[13] = '\0';
  			printf("\n注册码为:%s\n",serial);
  		}
  	}
  	else
  	{
  		printf("用户名长度检验失败~!");
  	}
 

--------------------------------------------------------------------------------
【经验总结】
  就是一堆加减乘除。。。不用程序来我还真看不清。呵呵。
  
--------------------------------------------------------------------------------
【版权声明】: 本文原创于creantan, 转载请注明作者并保持文章的完整, 谢谢!

                                                       2009年02月03日 22:11:58

[培训]内核驱动高级班,冲击BAT一流互联网大厂工 作,每周日13:00-18:00直播授课

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雪    币: 136
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szjohn 1 2009-2-3 22:53
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最近大家很活跃,很多人都写破文出来,顶一下,大家继续努力!!
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petnt 12 2009-2-3 23:34
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有条理,支持一下
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dreamzgj 2 2009-2-4 13:41
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好文章一定要收藏!

不过貌似是看雪crackme中的第一个crackMe

分析的蛮详细,注册机的写法很好! 支持!
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