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[结束][第一阶段◇第二题]看雪论坛.腾讯公司2008软件安全技术竞赛
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发表于: 2008-10-5 11:54
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啊，我以为是只有abcdefghijkl这几个字母
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不知道逆的对不对，刚才看了netwind贴出的说明才明白大致的模型原理，一直没想明白注册机该从何下手。
 if (strlen(g_szRegName) != 0xC) return 1;
for(i=0; i<strlen(g_szRegName); i++)
{
if (g_szRegName[i] < 0x61) return 1;
if (g_szRegName[i] >= 0x7A) return 1;
}
//dwSortIndex数组存放注册名中各字母按从小到大排序的名次
for(j=0; j<0xC; j++)
{
n = g_szRegName[0];
l = 0;
for(i = 1; i < strlen(g_szRegName); i++)
{
if ((n == g_szRegName[i]) && (n != 0x7A)) return 1;
if (n > g_szRegName[i])
{
n = g_szRegName[i];
l = i;
}
}
dwSortIndex[l] = j;
g_szRegName[l] = 0x7A;
}
if (strlen(g_szRegCode) < 0x35) return 1;
for(i=0; i<strlen(g_szRegCode); i++)
{
if (var_2B0[i] = g_szRegCode[i]-0x30) > 3) return 1;
}
chOutBuf[24] = 0;
fn(&var_2B0, &chOutBuf, &dwSortIndex);
pchOutBuf = &chOutBuf;
for(k=0; k<2; k++,pchOutBuf += 0xC)
{
for(j=0; j<0xC; j++)
{
n = pchOutBuf[0];
l = 0;
for(i=1; i<strlen(pchOutBuf)&&(i<0xC); var4++)
{
if (n == pchOutBuf[i]) && (n != 0x7A) return 1;
if (n > pchOutBuf[i])
{
n = pchOutBuf[i];
l = i;
}
}
if (k == 0)
dwOutSortIndex1[l] = j;
else
dwOutSortIndex2[l] = j;
pchOutBuf[l] = 0x7A;
}
}
//只要出来的两组数据按字母从小到大排序后和注册名的一致就算成功
for(i=0; i<0xC; i++)
{
if (dwSortIndex[i] != dwOutSortIndex1[i])||(dwSortIndex[i] != dwOutSortIndex2[i])||(dwOutSortIndex1[i] != dwOutSortIndex2[i]) return 1;
}
return 0;
void fn(int dwRegCode[53], char chOutBuf[24], int dwSortIndex[12])
{
int i, j, k, l, m, n, p, q, r, s, t, x, y;
int dwTemps[12];
int dwTempd[48];
l = 0;
for(i=0; i<0xC; i++) dwTemps[i] = 0x1E;
m = 0;
if (dwRegCode[0] > 0) m = 0xC/dwRegCode[0];
n = 0;
for(r=0; r<2; r++)
{
if (n > 0) dwTemps[dwSortIndex[n-1]] = 0x1E;
for(n=0; n<0xC;)
{
if (n > 0) dwTemps[dwSortIndex[n-1]] = 0x28;
if (r == 0) dwTemps[dwSortIndex[n]] = 0x28;
if (r == 1) dwTemps[dwSortIndex[n]] = 0x14;
n++;
for(k=0,i=0; i<dwRegCode[0]; i++)
{
for(j=0; j<m; j++)
{
dwTempd[i*4+j] = dwTemps[k];
k++;
}
}
p = 0;
q = 0;
for(i=0; i<m; i++)
{
p += dwTempd[dwRegCode[1]*4+i];
q += dwTempd[dwRegCode[2]*4+i];
}
if (p == q)
{
if (dwTempd[dwRegCode[3]*4+dwRegCode[4]] == dwTempd[dwRegCode[5]*4+dwRegCode[6]])
{
if (dwTempd[dwRegCode[7]*4+dwRegCode[8]] == dwTempd[dwRegCode[9]*4+dwRegCode[10]])
{
chOutBuf[l] = 0x6C;
l++;
}
else
{
chOutBuf[l] = 0x6B;
l++;
}
}
else
{
if (dwTempd[dwRegCode[7]*4+dwRegCode[8]] == dwTempd[dwRegCode[9]*4+dwRegCode[10]])
{
chOutBuf[l] = 0x6A;
l++;
}
else
{
chOutBuf[l] = 0x69;
l++;
}
}
}
if (p > q)
{
dwTempd[dwRegCode[1]*4+dwRegCode[11]] = dwTempd[dwRegCode[12]*4+dwRegCode[13]];
dwTempd[dwRegCode[1]*4+dwRegCode[14]] = dwTempd[dwRegCode[15]*4+dwRegCode[16]];
dwTempd[dwRegCode[1]*4+dwRegCode[17]] = dwTempd[dwRegCode[18]*4+dwRegCode[19]];
dwTempd[dwRegCode[2]*4+dwRegCode[20]] = dwTempd[dwRegCode[21]*4+dwRegCode[22]];
dwTempd[dwRegCode[2]*4+dwRegCode[23]] = dwTempd[dwRegCode[24]*4+dwRegCode[25]];
dwTempd[dwRegCode[2]*4+dwRegCode[26]] = dwTempd[dwRegCode[27]*4+dwRegCode[28]];
s = 0;
t = 0;
for(i=0; i<m; i++)
{
s += dwTempd[dwRegCode[1]*4+i];
t += dwTempd[dwRegCode[2]*4+i];
}
if (s > t)
{
if (dwTempd[dwRegCode[29]*4+dwRegCode[30]] == dwTempd[dwRegCode[31]*4+dwRegCode[32]])
{
chOutBuf[l] = 0x65;
l++;
}
else
{
chOutBuf[l] = 0x61;
l++;
}
}
if (s < t)
{
if (dwTempd[dwRegCode[33]*4+dwRegCode[34]] > dwTempd[dwRegCode[35]*4+dwRegCode[36]])
{
chOutBuf[l] = 0x67;
l++;
}
if (dwTempd[dwRegCode[33]*4+dwRegCode[34]] < dwTempd[dwRegCode[35]*4+dwRegCode[36]])
{
chOutBuf[l] = 0x66;
l++;
}
if (dwTempd[dwRegCode[33]*4+dwRegCode[34]] == dwTempd[dwRegCode[35]*4+dwRegCode[36]])
{
chOutBuf[l] = 0x68;
l++;
}
}
if (s == t)
{
k = 0;
for(i=0; i<dwRegCode[0]; i++)
{
for(j=0; j<m; j++)
{
dwTempd[i*4+j] = dwTemps[k];
k++;
}
}
if (dwTempd[dwRegCode[37]*4+dwRegCode[38]] > dwTempd[dwRegCode[39]*4+dwRegCode[40]])
{
chOutBuf[l] = 0x62;
l++;
}
if (dwTempd[dwRegCode[37]*4+dwRegCode[38]] < dwTempd[dwRegCode[39]*4+dwRegCode[40]])
{
chOutBuf[l] = 0x63;
l++;
}
if (dwTempd[dwRegCode[37]*4+dwRegCode[38]] == dwTempd[dwRegCode[39]*4+dwRegCode[40]])
{
chOutBuf[l] = 0x64;
l++;
}
}
}
if (p < q)
{
dwTempd[dwRegCode[1]*4+dwRegCode[11]] = dwTempd[dwRegCode[12]*4+dwRegCode[13]];
dwTempd[dwRegCode[1]*4+dwRegCode[14]] = dwTempd[dwRegCode[15]*4+dwRegCode[16]];
dwTempd[dwRegCode[1]*4+dwRegCode[17]] = dwTempd[dwRegCode[18]*4+dwRegCode[19]];
dwTempd[dwRegCode[2]*4+dwRegCode[20]] = dwTempd[dwRegCode[21]*4+dwRegCode[22]];
dwTempd[dwRegCode[2]*4+dwRegCode[23]] = dwTempd[dwRegCode[24]*4+dwRegCode[25]];
dwTempd[dwRegCode[2]*4+dwRegCode[26]] = dwTempd[dwRegCode[27]*4+dwRegCode[28]];
x = 0;
y = 0;
for(i=0; i<m; i++)
{
x += dwTempd[dwRegCode[1]*4+i];
y += dwTempd[dwRegCode[2]*4+i];
}
if (x > y)
{
if (dwTempd[dwRegCode[41]*4+dwRegCode[42]] > dwTempd[dwRegCode[43]*4+dwRegCode[44]])
{
chOutBuf[l] = 0x66;
l++;
}
if (dwTempd[dwRegCode[41]*4+dwRegCode[42]] < dwTempd[dwRegCode[43]*4+dwRegCode[44]])
{
chOutBuf[l] = 0x67;
l++;
}
if (dwTempd[dwRegCode[41]*4+dwRegCode[42]] < dwTempd[dwRegCode[43]*4+dwRegCode[44]])
{
chOutBuf[l] = 0x68;
l++;
}
}
if (x < y)
{
if (dwTempd[dwRegCode[45]*4+dwRegCode[46]] == dwTempd[dwRegCode[47]*4+dwRegCode[48]])
{
chOutBuf[l] = 0x65;
l++;
}
else
{
chOutBuf[l] = 0x61;
l++;
}
}
if (x == y)
{
k = 0;
for(i=0; i<dwRegCode[0]; i++)
{
for(j=0; j<m; j++)
{
dwTempd[i*4+j] = dwTemps[k];
k++;
}
}
if (dwTempd[dwRegCode[49]*4+dwRegCode[50]] > dwTempd[dwRegCode[51]*4+dwRegCode[52]])
{
chOutBuf[l] = 0x63;
l++;
}
if (dwTempd[dwRegCode[49]*4+dwRegCode[50]] < dwTempd[dwRegCode[51]*4+dwRegCode[52]])
{
chOutBuf[l] = 0x62;
l++;
}
if (dwTempd[dwRegCode[49]*4+dwRegCode[50]] == dwTempd[dwRegCode[51]*4+dwRegCode[52]])
{
chOutBuf[l] = 0x64;
l++;
}
}
}
}
}
}
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[QUOTE=海风月影;517983]楼上的int dwTempd[16]
应该改成 int dwTempd[6][4][/QUOTE] 在源代码中没看到它对应的空间大小，从实现上看应该是个2维数组，而且第二维应该是4， 因为程序中用到shl 4，不知6从何得出？ 
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yd啊!!!!!!!!!!!!!!!!!!!!
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人家是GIRL，真能轻易告知，
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什么时候能达到这个水平
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