能力值：
( LV8，RANK：130 )
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99 楼
抄一段，encrypt前面xor密钥那一块是原来代码里没有的：
typedef unsigned char byte;
typedef unsigned int word32;
/**
* The F-table byte permutation (see description of the G-box permutation)
*/
static const byte fTable[256] = {
0xa3,0xd7,0x09,0x83,0xf8,0x48,0xf6,0xf4,0xb3,0x21,0x15,0x78,0x99,0xb1,0xaf,0xf9,
0xe7,0x2d,0x4d,0x8a,0xce,0x4c,0xca,0x2e,0x52,0x95,0xd9,0x1e,0x4e,0x38,0x44,0x28,
0x0a,0xdf,0x02,0xa0,0x17,0xf1,0x60,0x68,0x12,0xb7,0x7a,0xc3,0xe9,0xfa,0x3d,0x53,
0x96,0x84,0x6b,0xba,0xf2,0x63,0x9a,0x19,0x7c,0xae,0xe5,0xf5,0xf7,0x16,0x6a,0xa2,
0x39,0xb6,0x7b,0x0f,0xc1,0x93,0x81,0x1b,0xee,0xb4,0x1a,0xea,0xd0,0x91,0x2f,0xb8,
0x55,0xb9,0xda,0x85,0x3f,0x41,0xbf,0xe0,0x5a,0x58,0x80,0x5f,0x66,0x0b,0xd8,0x90,
0x35,0xd5,0xc0,0xa7,0x33,0x06,0x65,0x69,0x45,0x00,0x94,0x56,0x6d,0x98,0x9b,0x76,
0x97,0xfc,0xb2,0xc2,0xb0,0xfe,0xdb,0x20,0xe1,0xeb,0xd6,0xe4,0xdd,0x47,0x4a,0x1d,
0x42,0xed,0x9e,0x6e,0x49,0x3c,0xcd,0x43,0x27,0xd2,0x07,0xd4,0xde,0xc7,0x67,0x18,
0x89,0xcb,0x30,0x1f,0x8d,0xc6,0x8f,0xaa,0xc8,0x74,0xdc,0xc9,0x5d,0x5c,0x31,0xa4,
0x70,0x88,0x61,0x2c,0x9f,0x0d,0x2b,0x87,0x50,0x82,0x54,0x64,0x26,0x7d,0x03,0x40,
0x34,0x4b,0x1c,0x73,0xd1,0xc4,0xfd,0x3b,0xcc,0xfb,0x7f,0xab,0xe6,0x3e,0x5b,0xa5,
0xad,0x04,0x23,0x9c,0x14,0x51,0x22,0xf0,0x29,0x79,0x71,0x7e,0xff,0x8c,0x0e,0xe2,
0x0c,0xef,0xbc,0x72,0x75,0x6f,0x37,0xa1,0xec,0xd3,0x8e,0x62,0x8b,0x86,0x10,0xe8,
0x08,0x77,0x11,0xbe,0x92,0x4f,0x24,0xc5,0x32,0x36,0x9d,0xcf,0xf3,0xa6,0xbb,0xac,
0x5e,0x6c,0xa9,0x13,0x57,0x25,0xb5,0xe3,0xbd,0xa8,0x3a,0x01,0x05,0x59,0x2a,0x46
};
/**
* The key-dependent permutation G on V^16 is a four-round Feistel network.
* The round function is a fixed byte-substitution table (permutation on V^8),
* the F-table. Each round of G incorporates a single byte from the key.
*/
#define g(tab, w, i, j, k, l) \
{ \
w ^= (word32)tab[i][w & 0xff] << 8; \
w ^= (word32)tab[j][w >> 8]; \
w ^= (word32)tab[k][w & 0xff] << 8; \
w ^= (word32)tab[l][w >> 8]; \
}
#define g0(tab, w) g(tab, w, 0, 1, 2, 3)
#define g1(tab, w) g(tab, w, 4, 5, 6, 7)
#define g2(tab, w) g(tab, w, 8, 9, 0, 1)
#define g3(tab, w) g(tab, w, 2, 3, 4, 5)
#define g4(tab, w) g(tab, w, 6, 7, 8, 9)
/**
* The inverse of the G permutation.
*/
#define h(tab, w, i, j, k, l) \
{ \
w ^= (word32)tab[l][w >> 8]; \
w ^= (word32)tab[k][w & 0xff] << 8; \
w ^= (word32)tab[j][w >> 8]; \
w ^= (word32)tab[i][w & 0xff] << 8; \
}
#define h0(tab, w) h(tab, w, 0, 1, 2, 3)
#define h1(tab, w) h(tab, w, 4, 5, 6, 7)
#define h2(tab, w) h(tab, w, 8, 9, 0, 1)
#define h3(tab, w) h(tab, w, 2, 3, 4, 5)
#define h4(tab, w) h(tab, w, 6, 7, 8, 9)
/**
* Preprocess a user key into a table to save an XOR at each F-table access.
*/
void makeKey(byte key[10], byte tab[10][256]) {
/* tab[i][c] = fTable[c ^ key[i]] */
int i;
for (i = 0; i < 10; i++) {
byte *t = tab[i], k = key[i];
int c;
for (c = 0; c < 256; c++) {
t[c] = fTable[c ^ k];
}
}
}
/**
* Encrypt a single block of data.
*/
void encrypt(byte tab[10][256], byte in[8], byte out[8]) {
word32 w1, w2, w3, w4;
w1 = (in[0] << 8) + in[1];
w2 = (in[2] << 8) + in[3];
w3 = (in[4] << 8) + in[5];
w4 = (in[6] << 8) + in[7];
/* stepping rule A: */
g0(tab, w1); w4 ^= w1 ^ 1;
g1(tab, w4); w3 ^= w4 ^ 2;
g2(tab, w3); w2 ^= w3 ^ 3;
g3(tab, w2); w1 ^= w2 ^ 4;
g4(tab, w1); w4 ^= w1 ^ 5;
g0(tab, w4); w3 ^= w4 ^ 6;
g1(tab, w3); w2 ^= w3 ^ 7;
g2(tab, w2); w1 ^= w2 ^ 8;
/* stepping rule B: */
w2 ^= w1 ^ 9; g3(tab, w1);
w1 ^= w4 ^ 10; g4(tab, w4);
w4 ^= w3 ^ 11; g0(tab, w3);
w3 ^= w2 ^ 12; g1(tab, w2);
w2 ^= w1 ^ 13; g2(tab, w1);
w1 ^= w4 ^ 14; g3(tab, w4);
w4 ^= w3 ^ 15; g4(tab, w3);
w3 ^= w2 ^ 16; g0(tab, w2);
/* stepping rule A: */
g1(tab, w1); w4 ^= w1 ^ 17;
g2(tab, w4); w3 ^= w4 ^ 18;
g3(tab, w3); w2 ^= w3 ^ 19;
g4(tab, w2); w1 ^= w2 ^ 20;
g0(tab, w1); w4 ^= w1 ^ 21;
g1(tab, w4); w3 ^= w4 ^ 22;
g2(tab, w3); w2 ^= w3 ^ 23;
g3(tab, w2); w1 ^= w2 ^ 24;
/* stepping rule B: */
w2 ^= w1 ^ 25; g4(tab, w1);
w1 ^= w4 ^ 26; g0(tab, w4);
w4 ^= w3 ^ 27; g1(tab, w3);
w3 ^= w2 ^ 28; g2(tab, w2);
w2 ^= w1 ^ 29; g3(tab, w1);
w1 ^= w4 ^ 30; g4(tab, w4);
w4 ^= w3 ^ 31; g0(tab, w3);
w3 ^= w2 ^ 32; g1(tab, w2);
out[0] = (byte)(w1 >> 8); out[1] = (byte)w1;
out[2] = (byte)(w2 >> 8); out[3] = (byte)w2;
out[4] = (byte)(w3 >> 8); out[5] = (byte)w3;
out[6] = (byte)(w4 >> 8); out[7] = (byte)w4;
}
/**
* Decrypt a single block of data.
*/
void decrypt(byte tab[10][256], byte in[8], byte out[8]) {
word32 w1, w2, w3, w4;
w1 = (in[0] << 8) + in[1];
w2 = (in[2] << 8) + in[3];
w3 = (in[4] << 8) + in[5];
w4 = (in[6] << 8) + in[7];
/* stepping rule A: */
h1(tab, w2); w3 ^= w2 ^ 32;
h0(tab, w3); w4 ^= w3 ^ 31;
h4(tab, w4); w1 ^= w4 ^ 30;
h3(tab, w1); w2 ^= w1 ^ 29;
h2(tab, w2); w3 ^= w2 ^ 28;
h1(tab, w3); w4 ^= w3 ^ 27;
h0(tab, w4); w1 ^= w4 ^ 26;
h4(tab, w1); w2 ^= w1 ^ 25;
/* stepping rule B: */
w1 ^= w2 ^ 24; h3(tab, w2);
w2 ^= w3 ^ 23; h2(tab, w3);
w3 ^= w4 ^ 22; h1(tab, w4);
w4 ^= w1 ^ 21; h0(tab, w1);
w1 ^= w2 ^ 20; h4(tab, w2);
w2 ^= w3 ^ 19; h3(tab, w3);
w3 ^= w4 ^ 18; h2(tab, w4);
w4 ^= w1 ^ 17; h1(tab, w1);
/* stepping rule A: */
h0(tab, w2); w3 ^= w2 ^ 16;
h4(tab, w3); w4 ^= w3 ^ 15;
h3(tab, w4); w1 ^= w4 ^ 14;
h2(tab, w1); w2 ^= w1 ^ 13;
h1(tab, w2); w3 ^= w2 ^ 12;
h0(tab, w3); w4 ^= w3 ^ 11;
h4(tab, w4); w1 ^= w4 ^ 10;
h3(tab, w1); w2 ^= w1 ^ 9;
/* stepping rule B: */
w1 ^= w2 ^ 8; h2(tab, w2);
w2 ^= w3 ^ 7; h1(tab, w3);
w3 ^= w4 ^ 6; h0(tab, w4);
w4 ^= w1 ^ 5; h4(tab, w1);
w1 ^= w2 ^ 4; h3(tab, w2);
w2 ^= w3 ^ 3; h2(tab, w3);
w3 ^= w4 ^ 2; h1(tab, w4);
w4 ^= w1 ^ 1; h0(tab, w1);
out[0] = (byte)(w1 >> 8); out[1] = (byte)w1;
out[2] = (byte)(w2 >> 8); out[3] = (byte)w2;
out[4] = (byte)(w3 >> 8); out[5] = (byte)w3;
out[6] = (byte)(w4 >> 8); out[7] = (byte)w4;
}
#include <stdio.h>
#include <string.h>
#include <time.h>
int main()
{
byte key[10] = {0x00, 0xB8, 0x29, 0x37, 0x40, 0x00, 0xC3, 0x8B, 0x10, 0x85};
byte tab[10][256];
byte inp[8] = "12345678";
byte enc[8];
int i;
makeKey(key, tab);
for (i=0;i<8;i++)
{
inp[i] ^= key[i];
}
encrypt(tab,inp,enc);
return 0;
}
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你咋不加油呢？
