这里是验证第一段序列号的逻辑
可以发现其实前8个字节被放进了dword_404000里，而且还测试了这个其实是个s盒，没有重复的数字。
所以可以确定前个8个字节是什么，但是并不知道它们之间的顺序是什么。
0x1e,0x28,0x4b,0x6d,0x8c,0xa3,0xd2,0xfb
确定顺序之后其实就可以爆破了，大概10分钟可以爆出来。
B4D682C8BF2DE13A 前16个序列号
后8个字节序列号的逻辑代码
最后要等于“GoodJob~”
得到前8个序列号后我们就可以进入这里面了，然后可以dump出dword_40400的数据，这里是对后8个字节进行加密。
这里也是采用爆破，这里可以单字节爆破，我是一个个字节来爆破的。
得到序列号:B4D682C8BF2DE13AD9B6AEF24A80CB22
do
{
byte_404220[0] = *((_BYTE *)&dword_404000 + v2 - 1);// 取第一个hex
byte_404221 = v2;
v3 = byte_404220;
v4 = &dword_404100;
v5 = &byte_404220[dword_404100];
do
{
v6 = *v4;
if ( *v4 > 0 )
{
do
{
v7 = v5 + 1;
*(v7 - 1) = *((_BYTE *)&dword_404000 + (unsigned __int8)*v3);
*v7 = *v3 + 1;
v5 = v7 + 1;
++v3;
--v6;
}
while ( v6 );
}
++v4;
}
while ( (int)v4 < (int)&unk_40411C );
v8 = 256;
do
{
++v25[(unsigned __int8)*v3++];
--v8;
}
while ( v8 );
++v2;
v25 += 256;
}
while ( v2 - 1 < 256 );
v9 = &unk_404448;
v10 = 256;
do
{
if ( *(v9 - 40) )
++v21;
if ( *(v9 - 26) )
++v22;
if ( *v9 )
++v23;
if ( v9[39] )
++v24;
v9 += 256;
--v10;
}
while ( v10 );
if ( v21 == (char)0xA9 && v22 == (char)0xAC && v23 == (char)0xA7 && v24 > 0xC8u )
do
{
byte_404220[0] = *((_BYTE *)&dword_404000 + v2 - 1);// 取第一个hex
byte_404221 = v2;
v3 = byte_404220;
v4 = &dword_404100;
v5 = &byte_404220[dword_404100];
do
{
v6 = *v4;
if ( *v4 > 0 )
{
do
{
v7 = v5 + 1;
*(v7 - 1) = *((_BYTE *)&dword_404000 + (unsigned __int8)*v3);
*v7 = *v3 + 1;
v5 = v7 + 1;
++v3;
--v6;
}
while ( v6 );
}
++v4;
}
while ( (int)v4 < (int)&unk_40411C );
v8 = 256;
do
{
++v25[(unsigned __int8)*v3++];
--v8;
}
while ( v8 );
++v2;
v25 += 256;
}
while ( v2 - 1 < 256 );
v9 = &unk_404448;
v10 = 256;
do
{
if ( *(v9 - 40) )
++v21;
if ( *(v9 - 26) )
++v22;
if ( *v9 )
++v23;
if ( v9[39] )
++v24;
v9 += 256;
--v10;
}
while ( v10 );
if ( v21 == (char)0xA9 && v22 == (char)0xAC && v23 == (char)0xA7 && v24 > 0xC8u )
import sys
a=[ 0xA2, 0x9B,
0xF4, 0xDF, 0xAC, 0x7C, 0xA1, 0xC6, 0x16, 0xD0, 0x0F, 0xDD,
0xDC, 0x73, 0xC5, 0x6B, 0xD1, 0x96, 0x47, 0xC2, 0x26, 0x67,
0x4E, 0x41, 0x82, 0x20, 0x56, 0x9A, 0x6E, 0x33, 0x92, 0x88,
0x29, 0xB5, 0xB4, 0x71, 0xA9, 0xCE, 0xC3, 0x34, 0x50, 0x59,
0xBF, 0x2D, 0x57, 0x22, 0xA6, 0x30, 0x04, 0xB2, 0xCD, 0x36,
0xD5, 0x68, 0x4D, 0x5B, 0x45, 0x9E, 0x85, 0xCF, 0x9D, 0xCC,
0x61, 0x78, 0x32, 0x76, 0x31, 0xE3, 0x80, 0xAD, 0x39, 0x4F,
0xFA, 0x72, 0x83, 0x4C, 0x86, 0x60, 0xB7, 0xD7, 0x63, 0x0C,
0x44, 0x35, 0xB3, 0x7B, 0x19, 0xD4, 0x69, 0x08, 0x0B, 0x1F,
0x3D, 0x11, 0x79, 0xD3, 0xEE, 0x93, 0x42, 0xDE, 0x23, 0x3B,
0x5D, 0x8D, 0xA5, 0x77, 0x5F, 0x58, 0xDB, 0x97, 0xF6, 0x7A,
0x18, 0x52, 0x15, 0x74, 0x25, 0x62, 0x2C, 0x05, 0xE8, 0x0D,
0x98, 0x2A, 0x43, 0xE2, 0xEF, 0x48, 0x87, 0x49, 0x1C, 0xCA,
0x2B, 0xA7, 0x8A, 0x09, 0x81, 0xE7, 0x53, 0xAA, 0xFF, 0x6F,
0x8E, 0x91, 0xF1, 0xF0, 0xA4, 0x46, 0x3A, 0x7D, 0x54, 0xEB,
0x2F, 0xC1, 0xC0, 0x0E, 0xBD, 0xE1, 0x6C, 0x64, 0xBE, 0xE4,
0x02, 0x3C, 0x5A, 0xA8, 0x9F, 0x37, 0xAF, 0xA0, 0x13, 0xED,
0x1B, 0xEC, 0x8B, 0x3E, 0x7E, 0x27, 0x99, 0x75, 0xAB, 0xFE,
0xD9, 0x3F, 0xF3, 0xEA, 0x70, 0xF7, 0x95, 0xBA, 0x1D, 0x40,
0xB0, 0xF9, 0xE5, 0xF8, 0x06, 0xBC, 0xB6, 0x03, 0xC9, 0x10,
0x9C, 0x2E, 0x89, 0x5C, 0x7F, 0xB1, 0x1A, 0xD6, 0x90, 0xAE,
0xDA, 0xE6, 0x5E, 0xB9, 0x84, 0xE9, 0x55, 0xBB, 0xC7, 0x0A,
0xE0, 0x66, 0xF2, 0xD8, 0xCB, 0x00, 0x12, 0xB8, 0x17, 0x94,
0x6A, 0x4A, 0x01, 0x24, 0x14, 0x51, 0x07, 0x65, 0x21, 0xC8,
0x38, 0xFD, 0x8F, 0xC4, 0xF5, 0xFC]
def check(d):
for i in d:
if d.count(i)>1:
return 1
return 0
burst_num =[0x1e,0x28,0x4b,0x6d,0x8c,0xa3,0xd2,0xfb]
def enc_fun(d):
e=[0 for i in range(256*256)]
f=[0 for i in range(512)]
v2 = 1
m = 0
for i in range(256):
f[0] = d[v2-1]
f[1] = v2&0xff
l = 0
for k in range(254):
f[2+k*2] = d[f[l]]
f[2+k*2+1] = (f[l] +1)&0xff
l+=1
for j in range(256):
e[m+f[l]] +=1
l+=1
v2+=1
m += 256
n=0
v21=0
v22=0
v23=0
v24=0
for i in range(256):
if e[n]:
v21+=1
if e[n+14]:
v22+=1
if e[n+40]:
v23+=1
if e[n+79]:
v24+=1
n+=256
if v24>0xc8:
print(hex(v21),hex(v22),hex(v23),hex(v24))
if v21 ==0xA9 and v22 ==0xAC and v23 ==0xA7 and v24 >0xc8:
return 1
return 0
def brust():
flag = 0
for i1 in burst_num:
for i2 in burst_num:
for i3 in burst_num:
for i4 in burst_num:
for i5 in burst_num:
for i6 in burst_num:
for i7 in burst_num:
for i8 in burst_num:
d = [i1,i2,i3,i4,i5,i6,i7,i8]
if check(d):
continue
d += a
if enc_fun(d):
print(i1,i2,i3,i4,i5,i6,i7,i8)
sys.exit()
if __name__ == '__main__':
brust()
import sys
a=[ 0xA2, 0x9B,
0xF4, 0xDF, 0xAC, 0x7C, 0xA1, 0xC6, 0x16, 0xD0, 0x0F, 0xDD,
0xDC, 0x73, 0xC5, 0x6B, 0xD1, 0x96, 0x47, 0xC2, 0x26, 0x67,
0x4E, 0x41, 0x82, 0x20, 0x56, 0x9A, 0x6E, 0x33, 0x92, 0x88,
0x29, 0xB5, 0xB4, 0x71, 0xA9, 0xCE, 0xC3, 0x34, 0x50, 0x59,
0xBF, 0x2D, 0x57, 0x22, 0xA6, 0x30, 0x04, 0xB2, 0xCD, 0x36,
0xD5, 0x68, 0x4D, 0x5B, 0x45, 0x9E, 0x85, 0xCF, 0x9D, 0xCC,
0x61, 0x78, 0x32, 0x76, 0x31, 0xE3, 0x80, 0xAD, 0x39, 0x4F,
0xFA, 0x72, 0x83, 0x4C, 0x86, 0x60, 0xB7, 0xD7, 0x63, 0x0C,
0x44, 0x35, 0xB3, 0x7B, 0x19, 0xD4, 0x69, 0x08, 0x0B, 0x1F,
0x3D, 0x11, 0x79, 0xD3, 0xEE, 0x93, 0x42, 0xDE, 0x23, 0x3B,
0x5D, 0x8D, 0xA5, 0x77, 0x5F, 0x58, 0xDB, 0x97, 0xF6, 0x7A,
0x18, 0x52, 0x15, 0x74, 0x25, 0x62, 0x2C, 0x05, 0xE8, 0x0D,
0x98, 0x2A, 0x43, 0xE2, 0xEF, 0x48, 0x87, 0x49, 0x1C, 0xCA,
0x2B, 0xA7, 0x8A, 0x09, 0x81, 0xE7, 0x53, 0xAA, 0xFF, 0x6F,
0x8E, 0x91, 0xF1, 0xF0, 0xA4, 0x46, 0x3A, 0x7D, 0x54, 0xEB,
0x2F, 0xC1, 0xC0, 0x0E, 0xBD, 0xE1, 0x6C, 0x64, 0xBE, 0xE4,
0x02, 0x3C, 0x5A, 0xA8, 0x9F, 0x37, 0xAF, 0xA0, 0x13, 0xED,
0x1B, 0xEC, 0x8B, 0x3E, 0x7E, 0x27, 0x99, 0x75, 0xAB, 0xFE,
0xD9, 0x3F, 0xF3, 0xEA, 0x70, 0xF7, 0x95, 0xBA, 0x1D, 0x40,
0xB0, 0xF9, 0xE5, 0xF8, 0x06, 0xBC, 0xB6, 0x03, 0xC9, 0x10,
0x9C, 0x2E, 0x89, 0x5C, 0x7F, 0xB1, 0x1A, 0xD6, 0x90, 0xAE,
0xDA, 0xE6, 0x5E, 0xB9, 0x84, 0xE9, 0x55, 0xBB, 0xC7, 0x0A,
0xE0, 0x66, 0xF2, 0xD8, 0xCB, 0x00, 0x12, 0xB8, 0x17, 0x94,
0x6A, 0x4A, 0x01, 0x24, 0x14, 0x51, 0x07, 0x65, 0x21, 0xC8,
0x38, 0xFD, 0x8F, 0xC4, 0xF5, 0xFC]
def check(d):
for i in d:
if d.count(i)>1:
return 1
return 0
burst_num =[0x1e,0x28,0x4b,0x6d,0x8c,0xa3,0xd2,0xfb]
def enc_fun(d):
e=[0 for i in range(256*256)]
f=[0 for i in range(512)]
v2 = 1
m = 0
for i in range(256):
f[0] = d[v2-1]
f[1] = v2&0xff
l = 0
for k in range(254):
f[2+k*2] = d[f[l]]
f[2+k*2+1] = (f[l] +1)&0xff
l+=1
for j in range(256):
e[m+f[l]] +=1
l+=1
v2+=1
m += 256
n=0
v21=0
v22=0
v23=0
v24=0
for i in range(256):
if e[n]:
v21+=1
if e[n+14]:
v22+=1
if e[n+40]:
v23+=1
if e[n+79]:
v24+=1
n+=256
if v24>0xc8:
print(hex(v21),hex(v22),hex(v23),hex(v24))
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最后于 2021-11-30 16:47
被n3ko编辑
，原因：
