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一道数学题求公式
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发表于: 2010-4-25 12:20
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要x可以无限增加 每加一次 鼠标点按照图中轨迹行走，找了好多大学同学都没有做出公式来，以前碰到过这个公式后来没用就忘记了，怎么找也找不到了，希望各位帮帮忙，帮我列出公式
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写了个C++类，完成你的功能了
代码很烂很烂 typedef enum
{
_RIGHT,
_DOWN,
_LEFT,
_UP
}JUST_DIR;
class CJustMath
{
public:
CJustMath(int x, int y, int step);
void GetPosition(int &x, int &y);
void mov();
virtual ~CJustMath();
private:
int m_x;
int m_y;
int m_step;
int m_times;
int m_Remember;
JUST_DIR m_Dir;
};
CJustMath::CJustMath(int x, int y, int step)
{
m_Dir = _RIGHT;
m_x = x;
m_y = y;
m_step = step;
m_times = 0;
m_Remember = 0;
}
CJustMath::~CJustMath()
{
}
void CJustMath::GetPosition(int &x, int &y)
{
x = m_x;
y = m_y;
}
void CJustMath::mov()
{
switch(m_Dir)
{
case _RIGHT:
if (m_Remember == 0)
m_times++;
while (m_Remember<m_times)
{
m_x += m_step;
m_Remember++;
return ;
}
m_Remember = 0;
m_Dir = _DOWN;
case _DOWN:
while (m_Remember<m_times)
{
m_y += m_step;
m_Remember++;
return ;
}
m_Remember = 0;
m_Dir = _LEFT;
case _LEFT:
if (m_Remember == 0)
m_times++;
while (m_Remember<m_times)
{
m_x -= m_step;
m_Remember++;
return ;
}
m_Remember = 0;
m_Dir = _UP;
case _UP:
while (m_Remember<m_times)
{
m_y -= m_step;
m_Remember++;
return ;
}
m_Remember = 0;
m_Dir = _RIGHT;
mov();
}
}
#include "stdafx.h"
#include "JustMath.h"
int main(int argc, char* argv[])
{
int x = 0;
int y = 0;
CJustMath justmath(33, 21, 1);
for (int i=0; i<13; i++)
{
justmath.GetPosition(x, y);
printf("(%d,%d)\r\n", x, y);
justmath.mov();
}
return 0;
}
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