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[转帖]Tuts 4 You - Collection 2011
EverBox 分流地址。 http://www.everbox.com/f/QFphpQIsKVlnq7SZL7DP6ioIKM 最近不知道是电信的问题还是everbox的问题,大文件上传总是出毛病,最后没办法,分卷压缩后传了一天…… |
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[转帖]Tuts 4 You - Collection 2011
EverBox还不错,现在还有活动额外赠送10G空间。单个文件大小无限制。 注册链接 http://account.everbox.com/signup/lummar |
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[讨论]ntdll 中 为什么有两套相同函数 ZwXXX 和 NtXXX ?
的确,用户态确实没什么区别。 内核态下,两者最大的区别在于Zw系列的函数会正确设置previousMode是用户态还是内核态。 参见下面的引文: The NtXxxx version of the native system service is the name of the function itself. Thus, when a Kernel Mode component calls the NtXxxx version of the system service, whatever is presently set into previous mode is unchanged. Thus, it is quite possible that the Kernel component could be running on an arbitrary User stack, with the requestor mode set to User. The system service will not know any better, attempt to validate the request parameters, possibly using the credentials of the arbitrary User Mode thread, and thus possibly fail the request. Another problem here is that one step in the validation process for a User Mode request is that all passed in bu®ers have either ProbeForRead or ProbeForWrite executed on them, depending on the bu®er's usage. These routines raise exceptions if executed on Kernel Mode addresses. Therefore, if you pass in Kernel Mode bu®ers with your request mode set to User, your calls into the native API return STATUS ACCESS VIOLATION. The moral of this bedtime story is that if you are in User Mode, use whatever variant you think makes your code look pretty. In Kernel Mode, use the ZwXxx routines and get your previous mode set properly, to Kernel Mode. |
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[招聘]Intel 招聘 资深底层安全高手~~(下一代芯片研发)
看不出这个职位跟底层有虾米关系 |
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[求助]学习32位汇编语言,CPU用32位的好,还是用64位的好?
应该没什么影响吧,再说,你现在貌似很难找个32位cpu |
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[求助]请问windows每个线程都有一个用户堆栈和内核堆栈是吗?
Windows Internals. |
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[转帖]Intel.C.Plus.Plus.Composer.XE.2011.5.221.ISO-TBE
这个太坑爹了,只能下550MB。。。。。。。 |
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[下载]最新Reflector 7.1.0.143(包含所有插件)
没有问题啊,跑得挺好的 |
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[招聘]英国某电子科技公司招聘初级软件工程师
啥都不说了 |
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[求助]谷歌的服务器难道是塑料做的?
你用一个http 分析工具监视一下,就什么都知道了 |
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