能力值:
(RANK:330 )
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2 楼
base[0x12FFC+iEax*4]
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能力值:
( LV2,RANK:10 )
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3 楼
没有结构,不是数组哦
难道是我逆错了?
.text:000111EA sub_111EA proc near ; CODE XREF: sub_11000+CFp
.text:000111EA
.text:000111EA arg_0 = dword ptr 4
.text:000111EA
.text:000111EA mov ecx, [esp+arg_0]
.text:000111EE mov eax, ecx
.text:000111F0 and eax, 0FFFFh
.text:000111F5 shr ecx, 10h
.text:000111F8 test eax, eax
.text:000111FA jz short loc_1120F
.text:000111FA
.text:000111FC cmp eax, 58h
.text:000111FF ja short loc_1120F
.text:000111FF
.text:00011201 cmp ecx, 3
.text:00011204 ja short loc_1120F
.text:00011204
.text:00011206 mov al, [ecx+eax*4+12FFCh]
.text:0001120D jmp short locret_11211
.text:0001120D
.text:0001120F ; 哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪哪?
.text:0001120F
.text:0001120F loc_1120F: ; CODE XREF: sub_111EA+10j
.text:0001120F ; sub_111EA+15j
.text:0001120F ; sub_111EA+1Aj
.text:0001120F xor al, al
.text:0001120F
.text:00011211
.text:00011211 locret_11211: ; CODE XREF: sub_111EA+23j
.text:00011211 retn 4
.text:00011211
.text:00011211 sub_111EA endp
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能力值:
( LV2,RANK:10 )
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4 楼
0x12FFC[HIWORD(iunknown)+LOWORD(iunknown)*4]
是不是应该是这样
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能力值:
(RANK:330 )
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5 楼
有source就好看多了
12FFCh是你驱动里的静态地址
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