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请教VB的问题
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2004-9-13 15:07
3969
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Const bPatch = "aDate.TXT"
Dim Filename As String
Private Sub Command1_Click()
'On Error GoTo exit1
Dim codate As String
Dim codate As String
Dim a As Long,a1 As Long
Filename = App.Path & "\" + aPatch
Open Filename For Binary As #1 '以二进制方式打开文件
Text1.Text = StrConv(InputB(LOF(1), #1), vbUnicode)
codate = StrConv(Text1.Text, vbUpperCase) '转换大写字母
a1 = Len(codate)
codatea = ""
For a = 1 To a1
codatea = Trim(codatea) & Trim(Mid(codate, a, 1)) '清除空字符//这里出问题
Next a
exit1:
Close #1 '关闭文件
'Unload Me '退出程序
End Sub
aText.TXT数据文件内容,该内容是在 OD 的 DUMP 区以二进制方式拷贝到记事本。
C7 44 24 04 80 00 40 00 A1 34 D8 63 00 C7 80 D4
9A 00 00 E9 85 00 00 C6 80 B1 9B 00 00 EB C6 80
1D 9C 00 00 EB C7 80 D0 9C 00 00 E9 94 00 00 C6
80 B8 9D 00 00 EB C6 80 26 6B 01 00 EB C7 80 26
6B 01 00 EB 00 00 00 C7 80 C3 6B 01 00 E9 89 00
00 E9 F6 21 18 00 90 90
问题:
在把文件读入变数codatea清除空字符后,在0x20h及0x40h处多了00,整个
长度多了两个字节,直接拷贝到文字方块并且手动把空字符去掉就不会有问题.
我错在那里请各位指点,谢谢。
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