本人刚学破解-刚刚破解的一个软件?
但是不知道有没有破解成功请高手们请教了???
:004018D0 BA78194000 mov edx, 00401978
:004018D5 A140494700 mov eax, dword ptr [00474940]
:004018DA 8B18 mov ebx, dword ptr [eax]
:004018DC FF5304 call [ebx+04]
:004018DF 8D55FC lea edx, dword ptr [ebp-04]
:004018E2 A138494700 mov eax, dword ptr [00474938]
:004018E7 8B80E8020000 mov eax, dword ptr [eax+000002E8]
:004018ED E8320A0300 call 00432324
:004018F2 8B45FC mov eax, dword ptr [ebp-04]
:004018F5 50 push eax
* Possible StringData Ref from Code Obj ->"RegNo"
|
:004018F6 B98C194000 mov ecx, 0040198C
* Possible StringData Ref from Code Obj ->"Register"
|
:004018FB BA78194000 mov edx, 00401978
:00401900 A140494700 mov eax, dword ptr [00474940]
:00401905 8B18 mov ebx, dword ptr [eax]
:00401907 FF5304 call [ebx+04]
* Reference To: Cargador.Regist::RegTwoWar(void())
|
:0040190A E8D5FCFFFF call 004015E4
:0040190F 803D3C49470000 cmp byte ptr [0047493C], 00
:00401916 750C jne 00401924--->>我把这个JNE改成JMP
* Possible StringData Ref from Code Obj ->"名字和注册号不匹配！请重新输入！"
|
:00401918 B89C194000 mov eax, 0040199C
:0040191D E8FEB70200 call 0042D120
:00401922 EB19 jmp 0040193D
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:00401916(C)
|
* Possible StringData Ref from Code Obj ->"恭喜你已经成功注册！"
|
:00401924 B8C8194000 mov eax, 004019C8
:00401929 E8F2B70200 call 0042D120
:0040192E A138494700 mov eax, dword ptr [00474938]
:00401933 C7802C02000001000000 mov dword ptr [ebx+0000022C], 00000001
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:00401922(U)
|
:0040193D 33C0 xor eax, eax
:0040193F 5A pop edx
:00401940 59 pop ecx
:00401941 59 pop ecx
:00401942 648910 mov dword ptr fs:[eax], edx
:00401945 685A194000 push 0040195A
下面这个是破解后的文件
附件:Cargador.rar
下面这个是原文件
附件:复件 Cargador.rar
[招生]科锐逆向工程师培训(2024年11月15日实地，远程教学同时开班, 第51期)
