题目描述

easy rsa192

运行环境

WIN10，VCRUNTIME140

公开组序列号

name: EA35B2C3F2B5FCE4

code: 20DB698F803FB15F6DFFBADD0E125ABEBE96494B0CCCA620

python版验证逻辑

def kctf2025_cm(name, code):

    n = 0x56F67550F16A00390DCF0B2715708E61C5B3F23101862FC1

    e = [0x03,0x07,0x0B,0x11,0x13,0x17,0x1D,0x1F,0x25]

    a = 2 ** 184

    x = int.from_bytes(bytes.fromhex(code), byteorder='big')

    for i in e:

        x = pow(x,i,n)

        x = gmpy2.invert(x,n)

        x = x + a

    h = 'KCTF2025'.encode('utf-8') + hashlib.md5(name.encode('utf-8')).digest()

    r = int.from_bytes(h, byteorder='big')

    if x == r:

        print('ok')

    else:

        print('error')

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