[原创]第四题-CTF对抗-看雪-安全社区|安全招聘|kanxue.com

[原创]第四题

发表于: 2021-5-14 15:07 5121

[原创]第四题

k1ee

2021-5-14 15:07

5121

中午吃个饭果然晚了，然后还花了一个小时才看出来是数独

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就是这个简单判断，后面的是AES解密，就不管了

sub_811000是数独校验，竟然看了那么久
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随便找个网站求解
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前面的是根据表来生成一个数独的输入
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out = [5, 0, 6, 0, 1, 9, 2, 3, 8, 0, 0, 1, 8, 3, 4, 0, 5, 0, 0, 0, 7, 6, 2, 0, 0, 1, 9, 7, 0, 8, 4, 6, 0, 9, 2, 5, 4, 5,

       3, 0, 9, 0, 7, 8, 6, 6, 9, 2, 0, 8, 7, 1, 0, 3,

       2, 8, 0, 0, 5, 6, 3, 0, 0, 0, 6, 0, 1, 7, 2, 8, 0, 0, 1, 7, 9, 3, 4, 0, 5, 0, 2]
 
tbl = "$BPV:ubfYp}]DtN>aT^MGmJQ#*Hr`O'wjic0!hdy{oZz-@n+?&%s_/g<e[W)XUxRFSLRA;.l=CEkvK-(q"

ans = ''
 
c = 0

x = 0

ts = tbl[x: x + 9]

for i in range(81):

    val = out[i]

    if val != 0:

        ans += ts[val - 1]

        c += 1

    if (i + 1) % 9 == 0:

        ans += chr(ord('9') - c)

        c = 0

        x += 9

        ts = tbl[x: x + 9]
 
print(ans)

out = [5, 0, 6, 0, 1, 9, 2, 3, 8, 0, 0, 1, 8, 3, 4, 0, 5, 0, 0, 0, 7, 6, 2, 0, 0, 1, 9, 7, 0, 8, 4, 6, 0, 9, 2, 5, 4, 5,