拖入IDA，通过搜索提示文本Wrong，定位到提示函数内部，返回一层F5得到如下代码

BOOL __thiscall sub_401990(CWnd *this)
{
  struct CString *v1; // ST04_4
  CWnd *v2; // eax
  int v3; // eax
  BOOL result; // eax
  int v5; // [esp+0h] [ebp-6Ch]
  int v6; // [esp+4Ch] [ebp-20h]
  char *Str; // [esp+50h] [ebp-1Ch]
  int v8; // [esp+54h] [ebp-18h]
  CWnd *v9; // [esp+58h] [ebp-14h]
  int *v10; // [esp+5Ch] [ebp-10h]
  int v11; // [esp+68h] [ebp-4h]

  v10 = &v5;
  v9 = this;
  v11 = 0;
  ((void (*)(void))loc_4019BE)();
  v8 = 668;
  MEMORY[0x29C] = 6;
  v11 = -1;
  v1 = (CWnd *)((char *)v9 + 96);
  v2 = CWnd::GetDlgItem(v9, 1002);
  CWnd::GetWindowTextA(v2, v1);
  v3 = sub_401AB0((char *)v9 + 96);
  Str = CString::GetBuffer((CWnd *)((char *)v9 + 96), v3);
  v6 = atoi(Str);
  if ( v6 / 2 == 80 )
    result = RightBox();
  else
    result = WrongBox();
  return result;
}

很明显的正确的判断条件是v6/2=80 也就是说满足正确的结果是80*2=160
而v6是通过atoi这个函数得来的，逆函数位itoa所以正确的注册码为
字符串形式的160

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