校验flag逻辑:
运行脚本,得到flag:j0rXI4bTeustBiIGHeCF70DDM
j0rXI4bTeustBiIGHeCF70DDM
flag_index
=
'0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
flag
[]
encrypt_index
'abcdefghiABCDEFGHIJKLMNjklmn0123456789opqrstuvwxyzOPQRSTUVWXYZ'
encflag
'KanXueCTF2019JustForhappy'
for
i
in
encflag:
flag.extend(flag_index[
int
(encrypt_index.find(i))])
flag:
print
(i, end
'')
KanXueCTF2019JustForhappy
[注意]看雪招聘,专注安全领域的专业人才平台!