部分加密算法，其他的算法目前没有找到
private static final char[] b = { 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 65, 66, 67, 68, 69, 70 };
public static String a(byte[] paramArrayOfByte)
  {
    if ((paramArrayOfByte == null) || (paramArrayOfByte.length == 0))
      return null;
    char[] arrayOfChar = new char[paramArrayOfByte.length * 2];
    int i = 0;
    while (i < paramArrayOfByte.length)
    {
      int j = paramArrayOfByte[i];
      arrayOfChar[(i * 2 + 1)] = b[(j & 0xF)];
      j = (byte)(j >>> 4);
      arrayOfChar[(i * 2 + 0)] = b[(j & 0xF)];
      i += 1;
    }
    return new String(arrayOfChar);
  }

已知一个参数被加密成
986026b2e526ea45021e52378c80eb56311b6bf3e2648b2d45d6c3cd7cebe78e9277cbb68dbd08eb0d72a4b05679a52d66b982765ca4e13c83c79d93513410150fd0f01f19fc71f8b8923a49132fdac2af2c0962b73e8a36cc3fac73e3e1a6b6b65567e2d0b8a967797cd0feeac22e4285ed282503ea3e36132f725eaea271fd0e31761a47c5992d71217220e1f6bf32a440372986635ad74ff6d44c9e435cd263be2421ced18bc5772e562cdeffcf07d8ae9b96b48f548f8b2827feeed93e7b5ce3644296ee8d6174ac92f8a7d6f0112af5ada139829eab0235939c3cae29242dc586a094364d3ef6b9115227109982
通过上面算法
-104,96,38,-78,-27,38,-22,69,2,30,82,55,-116,-128,-21,86,49,27,107,-13,-30,100,-117,45,69,-42,-61,-51,124,-21,-25,-114,-110,119,-53,-74,-115,-67,8,-21,13,114,-92,-80,86,121,-91,45,102,-71,-126,118,92,-92,-31,60,-125,-57,-99,-109,81,52,16,21,15,-48,-16,31,25,-4,113,-8,-72,-110,58,73,19,47,-38,-62,-81,44,9,98,-73,62,-118,54,-52,63,-84,115,-29,-31,-90,-74,-74,85,103,-30,-48,-72,-87,103,121,124,-48,-2,-22,-62,46,66,-123,-19,40,37,3,-22,62,54,19,47,114,94,-82,-94,113,-3,14,49,118,26,71,-59,-103,45,113,33,114,32,-31,-10,-65,50,-92,64,55,41,-122,99,90,-41,79,-10,-44,76,-98,67,92,-46,99,-66,36,33,-50,-47,-117,-59,119,46,86,44,-34,-1,-49,7,-40,-82,-101,-106,-76,-113,84,-113,-117,40,39,-2,-18,-39,62,123,92,-29,100,66,-106,-18,-115,97,116,-84,-110,-8,-89,-42,-16,17,42,-11,-83,-95,57,-126,-98,-85,2,53,-109,-100,60,-82,41,36,45,-59,-122,-96,-108,54,77,62,-10,-71,17,82,39,16,-103,-126
得出这个，然后不知道怎么进行下去

已知有参数
电话：18910640358
密码：acer0216

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