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[旧帖] [求助]远程线程注入后,对话框搞出来以后不能用... 0.00雪花
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发表于: 2013-1-21 00:19 1303
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dllmain里我是这样创建线程的:
BOOL APIENTRY DllMain(HINSTANCE hinstDLL,DWORD fdwReason,LPVOID lpvReserved)
{
char szProcessId[64];
switch (fdwReason)
{
case DLL_PROCESS_ATTACH:
MessageBox(NULL,TEXT("DLL进程注入成功!"),TEXT("提示"),MB_OK);
HANDLE m_hThread;
m_hThread=CreateThread(NULL,0,startMainDlg,0,0,NULL);
break;
case DLL_THREAD_ATTACH:
break;
case DLL_THREAD_DETACH:
break;
case DLL_PROCESS_DETACH:
break;
}
return TRUE;
}
下面是创建窗口的函数:
DWORD __stdcall startMainDlg(LPVOID lpParameter)
{
hwndDLG = CreateDialog(hinst,MAKEINTRESOURCE(IDD_DLG_MAIN), NULL,(DLGPROC)DlgProc);
ShowWindow(hwndDLG, SW_SHOW);
return 0;
}
按我上面这样写,对话框一闪而过。我从网上搜了搜资料说是因为需要加上消息循环,
如果我加上消息循环,改成这样:
DWORD __stdcall startMainDlg(LPVOID lpParameter)
{
hwndDLG = CreateDialog(hinst,MAKEINTRESOURCE(IDD_DLG_MAIN), NULL,(DLGPROC)DlgProc);
ShowWindow(hwndDLG, SW_SHOW);
bool flag = true;
MSG msg;
while(GetMessage(&msg,hwndDLG,0,0))
{
TranslateMessage(&msg);
DispatchMessage(&msg);
}
return 0;
}
对话框倒是出来了,结果上面的按钮什么的都没法用了,这是为啥?搜资料没找到原因,求大神帮忙看看
BOOL APIENTRY DllMain(HINSTANCE hinstDLL,DWORD fdwReason,LPVOID lpvReserved)
{
char szProcessId[64];
switch (fdwReason)
{
case DLL_PROCESS_ATTACH:
MessageBox(NULL,TEXT("DLL进程注入成功!"),TEXT("提示"),MB_OK);
HANDLE m_hThread;
m_hThread=CreateThread(NULL,0,startMainDlg,0,0,NULL);
break;
case DLL_THREAD_ATTACH:
break;
case DLL_THREAD_DETACH:
break;
case DLL_PROCESS_DETACH:
break;
}
return TRUE;
}
下面是创建窗口的函数:
DWORD __stdcall startMainDlg(LPVOID lpParameter)
{
hwndDLG = CreateDialog(hinst,MAKEINTRESOURCE(IDD_DLG_MAIN), NULL,(DLGPROC)DlgProc);
ShowWindow(hwndDLG, SW_SHOW);
return 0;
}
按我上面这样写,对话框一闪而过。我从网上搜了搜资料说是因为需要加上消息循环,
如果我加上消息循环,改成这样:
DWORD __stdcall startMainDlg(LPVOID lpParameter)
{
hwndDLG = CreateDialog(hinst,MAKEINTRESOURCE(IDD_DLG_MAIN), NULL,(DLGPROC)DlgProc);
ShowWindow(hwndDLG, SW_SHOW);
bool flag = true;
MSG msg;
while(GetMessage(&msg,hwndDLG,0,0))
{
TranslateMessage(&msg);
DispatchMessage(&msg);
}
return 0;
}
对话框倒是出来了,结果上面的按钮什么的都没法用了,这是为啥?搜资料没找到原因,求大神帮忙看看
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