00415AC0 /. 55 push ebp
00415AC1 |. 8BEC mov ebp,esp
00415AC3 |. 51 push ecx
00415AC4 |. 56 push esi
00415AC5 |. 8BF1 mov esi,ecx
00415AC7 |. 8D45 08 lea eax,dword ptr ss:[ebp+0x8]
00415ACA |. 50 push eax
00415ACB |. 8D4D FC lea ecx,dword ptr ss:[ebp-0x4]
00415ACE |. 51 push ecx
00415ACF |. 8D4E 50 lea ecx,dword ptr ds:[esi+0x50]
00415AD2 |. E8 29FB1E00 call Game.00605600
00415AD7 |. 8B4E 54 mov ecx,dword ptr ds:[esi+0x54]
00415ADA |. 8B45 FC mov eax,dword ptr ss:[ebp-0x4]
00415ADD |. 3BC1 cmp eax,ecx
00415ADF |. 5E pop esi
00415AE0 |. 75 08 jnz XGame.00415AEA
00415AE2 |. 33C0 xor eax,eax
00415AE4 |. 8BE5 mov esp,ebp
00415AE6 |. 5D pop ebp
00415AE7 |. C2 0400 retn 0x4
00415AEA |> 8B40 10 mov eax,dword ptr ds:[eax+0x10]
00415AED |. 8BE5 mov esp,ebp
00415AEF |. 5D pop ebp
00415AF0 \. C2 0400 retn 0x4
进入 这个CALL 来到最后这里 得到 eax=eax+10 继续向上追溯EAX来源
mov eax,dword ptr ss:[ebp-0x4]到这里 我问别人 说是 这里EAX是
00415AD2 |. E8 29FB1E00 call Game.00605600的返回值于是我进入这个CALL
00605600 /$ 55 push ebp
00605601 |. 8BEC mov ebp,esp
00605603 |. 51 push ecx
00605604 |. 8B51 04 mov edx,dword ptr ds:[ecx+0x4]
00605607 |. 8B42 04 mov eax,dword ptr ds:[edx+0x4]
0060560A |. 53 push ebx
0060560B |. 8A58 15 mov bl,byte ptr ds:[eax+0x15]
0060560E |. 84DB test bl,bl
00605610 |. 56 push esi
00605611 |. 57 push edi
00605612 |. 8B7D 0C mov edi,dword ptr ss:[ebp+0xC]
00605615 |. 75 1E jnz XGame.00605635
00605617 |. 8B37 mov esi,dword ptr ds:[edi]
00605619 |. 8DA424 000000>lea esp,dword ptr ss:[esp]
00605620 |> 3970 0C /cmp dword ptr ds:[eax+0xC],esi
00605623 |. 7D 05 |jge XGame.0060562A
00605625 |. 8B40 08 |mov eax,dword ptr ds:[eax+0x8]
00605628 |. EB 04 |jmp XGame.0060562E
0060562A |> 8BD0 |mov edx,eax
0060562C |. 8B00 |mov eax,dword ptr ds:[eax]
0060562E |> 8A58 15 |mov bl,byte ptr ds:[eax+0x15]
00605631 |. 84DB |test bl,bl
00605633 |.^ 74 EB \je XGame.00605620
00605635 |> 8B41 04 mov eax,dword ptr ds:[ecx+0x4]
00605638 |. 3BD0 cmp edx,eax
0060563A |. 8955 0C mov dword ptr ss:[ebp+0xC],edx
0060563D |. 74 1A je XGame.00605659
0060563F |. 8B0F mov ecx,dword ptr ds:[edi]
00605641 |. 3B4A 0C cmp ecx,dword ptr ds:[edx+0xC]
00605644 |. 7C 13 jl XGame.00605659
00605646 |. 8D45 0C lea eax,dword ptr ss:[ebp+0xC]
00605649 |. 8B10 mov edx,dword ptr ds:[eax]
0060564B |. 8B45 08 mov eax,dword ptr ss:[ebp+0x8]
0060564E |. 5F pop edi
0060564F |. 5E pop esi
00605650 |. 8910 mov dword ptr ds:[eax],edx
00605652 |. 5B pop ebx
00605653 |. 8BE5 mov esp,ebp
00605655 |. 5D pop ebp
00605656 |. C2 0800 retn 0x8
00605659 |> 8945 FC mov dword ptr ss:[ebp-0x4],eax
0060565C |. 8D45 FC lea eax,dword ptr ss:[ebp-0x4]
0060565F |. 8B10 mov edx,dword ptr ds:[eax]
00605661 |. 8B45 08 mov eax,dword ptr ss:[ebp+0x8]
00605664 |. 5F pop edi
00605665 |. 5E pop esi
00605666 |. 8910 mov dword ptr ds:[eax],edx
00605668 |. 5B pop ebx
00605669 |. 8BE5 mov esp,ebp
0060566B |. 5D pop ebp
0060566C \. C2 0800 retn 0x8
到这里以后 我就完全迷糊了 求解啊
根据别人 提过的答案是 mov dword ptr ds:[eax],edx 这里 然后继续追溯EDX
我想知道的是 怎么判断得到 这句就是我要要得值呢
[培训]内核驱动高级班,冲击BAT一流互联网大厂工作,每周日13:00-18:00直播授课