【文章标题】: AHpack分析
004040FF > 60 pushad ; 保存FPU寄存器
00404100 68 54404000 push 00404054 ; 直接硬件地址
00404105 B8 48404000 mov eax, <&KERNEL32.GetModuleHandleA>
0040410A FF10 call dword ptr [eax] ; ; kernel32.GetModuleHandleA
0040410C 68 B3404000 push 004040B3 ; 硬件编码，GlobalAlloc
00404111 50 push eax
00404112 B8 44404000 mov eax, <&KERNEL32.GetProcAddress>
00404117 FF10 call dword ptr [eax] ; 获取函数后，直接调用
00404119 68 00080000 push 800 ; 分配Size
0040411E 6A 40 push 40 ; 分配属性
00404120 FFD0 call eax
00404122 8905 CA404000 mov dword ptr [4040CA], eax ; Bak Flags
00404128 89C7 mov edi, eax ; Edi作目的地址
0040412A BE 00104000 mov esi, 00401000 ; 源地址
0040412F 60 pushad ; 这里就是Aplib压缩算法
00404130 FC cld
00404131 B2 80 mov dl, 80
00404133 31DB xor ebx, ebx
00404135 A4 movs byte ptr es:[edi], byte ptr [esi>
00404136 B3 02 mov bl, 2
00404138 E8 6D000000 call 004041AA
0040413D ^ 73 F6 jnb short 00404135
0040413F 31C9 xor ecx, ecx
00404141 E8 64000000 call 004041AA
00404146 73 1C jnb short 00404164
00404148 31C0 xor eax, eax
0040414A E8 5B000000 call 004041AA
0040414F 73 23 jnb short 00404174
00404151 B3 02 mov bl, 2
00404153 41 inc ecx
00404154 B0 10 mov al, 10
00404156 E8 4F000000 call 004041AA
0040415B 10C0 adc al, al
0040415D ^ 73 F7 jnb short 00404156
0040415F 75 3F jnz short 004041A0
00404161 AA stos byte ptr es:[edi]
00404162 ^ EB D4 jmp short 00404138
00404164 E8 4D000000 call 004041B6
00404169 29D9 sub ecx, ebx
0040416B 75 10 jnz short 0040417D
0040416D E8 42000000 call 004041B4
00404172 EB 28 jmp short 0040419C
00404174 AC lods byte ptr [esi]
00404175 D1E8 shr eax, 1
00404177 74 4D je short 004041C6
00404179 11C9 adc ecx, ecx
0040417B EB 1C jmp short 00404199
0040417D 91 xchg eax, ecx
0040417E 48 dec eax
0040417F C1E0 08 shl eax, 8
00404182 AC lods byte ptr [esi]
00404183 E8 2C000000 call 004041B4
00404188 3D 007D0000 cmp eax, 7D00
0040418D 73 0A jnb short 00404199
0040418F 80FC 05 cmp ah, 5
00404192 73 06 jnb short 0040419A
00404194 83F8 7F cmp eax, 7F
00404197 77 02 ja short 0040419B
00404199 41 inc ecx
0040419A 41 inc ecx
0040419B 95 xchg eax, ebp
0040419C 89E8 mov eax, ebp
0040419E B3 01 mov bl, 1
004041A0 56 push esi
004041A1 89FE mov esi, edi
004041A3 29C6 sub esi, eax
004041A5 F3:A4 rep movs byte ptr es:[edi], byte ptr>
004041A7 5E pop esi
004041A8 ^ EB 8E jmp short 00404138
004041AA 00D2 add dl, dl
004041AC 75 05 jnz short 004041B3
004041AE 8A16 mov dl, byte ptr [esi]
004041B0 46 inc esi
004041B1 10D2 adc dl, dl
004041B3 C3 retn
004041B4 31C9 xor ecx, ecx
004041B6 41 inc ecx
004041B7 E8 EEFFFFFF call 004041AA
004041BC 11C9 adc ecx, ecx
004041BE E8 E7FFFFFF call 004041AA
004041C3 ^ 72 F2 jb short 004041B7
004041C5 C3 retn
004041C6 61 popad
004041C7 B9 FC070000 mov ecx, 7FC ; 直接赋值硬件Size
004041CC 8B1C08 mov ebx, dword ptr [eax+ecx]
004041CF 8999 00104000 mov dword ptr [ecx+401000], ebx
004041D5 ^ E2 F5 loopd short 004041CC ; 解码
004041D7 90 nop
004041D8 90 nop
004041D9 BA 00004000 mov edx, 00400000
004041DE BE 70200000 mov esi, 2070 ; 直接引用IAT地址
004041E3 01D6 add esi, edx
004041E5 8B46 0C mov eax, dword ptr [esi+C] ; 获取IID NAME
004041E8 85C0 test eax, eax
004041EA 0F84 87000000 je 00404277
004041F0 01D0 add eax, edx
004041F2 89C3 mov ebx, eax
004041F4 50 push eax
004041F5 B8 48404000 mov eax, <&KERNEL32.GetModuleHandleA>
004041FA FF10 call dword ptr [eax] ; 获取NAME模块句柄
004041FC 85C0 test eax, eax
004041FE 75 08 jnz short 00404208 ; 获取不到调用LoadLibraryA
00404200 53 push ebx
00404201 B8 4C404000 mov eax, <&KERNEL32.LoadLibraryA>
00404206 FF10 call dword ptr [eax]
00404208 8905 CE404000 mov dword ptr [4040CE], eax ; 作者作一次判断就决定LoadLibraryA肯定获取得到！当前作Flags
0040420E C705 D2404000 0>mov dword ptr [4040D2], 0 ; 将模块句柄作标志Flags区分
00404218 BA 00004000 mov edx, 00400000
0040421D 8B06 mov eax, dword ptr [esi] ; 获取OriginalFirstThunk
0040421F 85C0 test eax, eax
00404221 75 03 jnz short 00404226 ; 如果获取不到就获取FirstThunk
00404223 8B46 10 mov eax, dword ptr [esi+10]
00404226 01D0 add eax, edx
00404228 0305 D2404000 add eax, dword ptr [4040D2] ; 加上模块句柄的Flags
0040422E 8B18 mov ebx, dword ptr [eax] ; 取这个是作判断
00404230 8B7E 10 mov edi, dword ptr [esi+10] ; 最后还是使用FirstThunk
00404233 01D7 add edi, edx
00404235 033D D2404000 add edi, dword ptr [4040D2]
0040423B 85DB test ebx, ebx ; 奇怪？？？？ 呵呵 (判断DLL)
0040423D 74 2B je short 0040426A
0040423F F7C3 00000080 test ebx, 80000000 ; 判断高位
00404245 75 04 jnz short 0040424B
00404247 01D3 add ebx, edx
00404249 43 inc ebx
0040424A 43 inc ebx
0040424B 81E3 FFFFFF0F and ebx, 0FFFFFFF ; 与是否符合位
00404251 53 push ebx
00404252 FF35 CE404000 push dword ptr [4040CE]
00404258 B8 44404000 mov eax, <&KERNEL32.GetProcAddress>
0040425D FF10 call dword ptr [eax]
0040425F 8907 mov dword ptr [edi], eax
00404261 8305 D2404000 0>add dword ptr [4040D2], 4
00404268 ^ EB AE jmp short 00404218
0040426A 83C6 14 add esi, 14
0040426D BA 00004000 mov edx, 00400000
00404272 ^ E9 6EFFFFFF jmp 004041E5
00404277 68 54404000 push 00404054 ; ASCII "KERNEL32.DLL"
0040427C B8 48404000 mov eax, <&KERNEL32.GetModuleHandleA>
00404281 FF10 call dword ptr [eax]
00404283 68 BF404000 push 004040BF ; ASCII "GlobalFree"
00404288 50 push eax
00404289 B8 44404000 mov eax, <&KERNEL32.GetProcAddress>
0040428E FF10 call dword ptr [eax]
00404290 8B15 CA404000 mov edx, dword ptr [4040CA]
00404296 52 push edx
00404297 FFD0 call eax ; GlobalFree
00404299 61 popad
0040429A BA 00104000 mov edx, 00401000
0040429F FFE2 jmp edx
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