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[求助]寻找哈希值一样的字符串
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发表于: 2010-7-9 13:03 4359
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原函数:
public override unsafe int GetHashCode()
{
fixed (char* str = ((char*) this))
{
char* chPtr = str;
int num = 0x15051505;
int num2 = num;
int* numPtr = (int*) chPtr;
for (int i = this.Length; i > 0; i -= 4)
{
num = (((num << 5) + num) + (num >> 0x1b)) ^ numPtr[0];
if (i <= 2)
{
break;
}
num2 = (((num2 << 5) + num2) + (num2 >> 0x1b)) ^ numPtr[1];
numPtr += 2;
}
return (num + (num2 * 0x5d588b65));
}
}
把this替换成参数:
public unsafe int GetValue(string s)
{
fixed (char* str = s)
{
char* chPtr = str;
int num = 0x15051505;
int num2 = num;
int* numPtr = (int*)chPtr;
for (int i = s.Length; i > 0; i -= 4)
{
num = (((num << 5) + num) + (num >> 0x1b)) ^ numPtr[0];
if (i <= 2)
{
break;
}
num2 = (((num2 << 5) + num2) + (num2 >> 0x1b)) ^ numPtr[1];
numPtr += 2;
}
return (num + (num2 * 0x5d588b65));
}
}
找出返回值相同的两个string
public override unsafe int GetHashCode()
{
fixed (char* str = ((char*) this))
{
char* chPtr = str;
int num = 0x15051505;
int num2 = num;
int* numPtr = (int*) chPtr;
for (int i = this.Length; i > 0; i -= 4)
{
num = (((num << 5) + num) + (num >> 0x1b)) ^ numPtr[0];
if (i <= 2)
{
break;
}
num2 = (((num2 << 5) + num2) + (num2 >> 0x1b)) ^ numPtr[1];
numPtr += 2;
}
return (num + (num2 * 0x5d588b65));
}
}
把this替换成参数:
public unsafe int GetValue(string s)
{
fixed (char* str = s)
{
char* chPtr = str;
int num = 0x15051505;
int num2 = num;
int* numPtr = (int*)chPtr;
for (int i = s.Length; i > 0; i -= 4)
{
num = (((num << 5) + num) + (num >> 0x1b)) ^ numPtr[0];
if (i <= 2)
{
break;
}
num2 = (((num2 << 5) + num2) + (num2 >> 0x1b)) ^ numPtr[1];
numPtr += 2;
}
return (num + (num2 * 0x5d588b65));
}
}
找出返回值相同的两个string
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