能力值：
( LV2，RANK：10 )
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2 楼
00453867 55 push ebp
00453868 68 E9384500 push Project1.004538E9
0045386D 64:FF30 push dword ptr fs:[eax]
00453870 64:8920 mov dword ptr fs:[eax],esp
00453873 8D55 EC lea edx,dword ptr ss:[ebp-14]
00453876 8B83 00030000 mov eax,dword ptr ds:[ebx+300]
0045387C E8 0FF2FDFF call Project1.00432A90 ; 取用户名
00453881 8B45 EC mov eax,dword ptr ss:[ebp-14]
00453884 E8 E358FBFF call Project1.0040916C
00453889 DD5D F8 fstp qword ptr ss:[ebp-8]
0045388C 9B wait
0045388D 8D55 E8 lea edx,dword ptr ss:[ebp-18]
00453890 8B83 04030000 mov eax,dword ptr ds:[ebx+304]
00453896 E8 F5F1FDFF call Project1.00432A90 ; 取密码
0045389B 8B45 E8 mov eax,dword ptr ss:[ebp-18]
0045389E E8 C958FBFF call Project1.0040916C ; 关键call
004538A3 DD5D F0 fstp qword ptr ss:[ebp-10]
004538A6 9B wait
004538A7 DD45 F8 fld qword ptr ss:[ebp-8]
004538AA DC4D F0 fmul qword ptr ss:[ebp-10]
004538AD D81D F8384500 fcomp dword ptr ds:[4538F8]
004538B3 DFE0 fstsw ax
004538B5 9E sahf
004538B6 75 0C jnz short Project1.004538C4 ; 关键跳
004538B8 B8 04394500 mov eax,Project1.00453904 ; ASCII "crack ok!"
004538BD E8 EE3AFDFF call Project1.004273B0
004538C2 EB 0A jmp short Project1.004538CE
004538C4 B8 18394500 mov eax,Project1.00453918 ; ASCII "Username or password is wrong!"
还是不会分析算法，不过我看着应该是很大的算数
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能力值：
( LV2，RANK：10 )
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3 楼
e语言有时候很会吓人
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能力值：
( LV3，RANK：20 )
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4 楼
不是E语言，呵呵！
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能力值：
( LV2，RANK：10 )
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5 楼
Delphi 写的！
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能力值：
( LV2，RANK：10 )
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6 楼
[QUOTE=王心生;813784]00453867 55 push ebp
00453868 68 E9384500 push Project1.004538E9
0045386D 64:FF30 push dword ptr fs:[eax]
0045387...[/QUOTE]
用户名*密码==585858;别人用IDA-F5秒杀出来的,我居然忘记我最擅长的IDA-F5了...
int __fastcall TForm1_Button1Click(int a1)
{
int v1; // ebx@1
int v3; // [sp-Ch] [bp-28h]@1
int (*v4)(); // [sp-8h] [bp-24h]@1
int (*v5)(); // [sp-4h] [bp-20h]@1
int v6; // [sp+4h] [bp-18h]@1
int v7; // [sp+8h] [bp-14h]@1
double v8; // [sp+Ch] [bp-10h]@1
double v9; // [sp+14h] [bp-8h]@1
int v10; // [sp+1Ch] [bp+0h]@1
v6 = 0;
v7 = 0;
v1 = a1;
v5 = (int (*)())&v10;
v4 = loc_4538E9;
v3 = *MK_FP(__FS__, 0);
*MK_FP(__FS__, 0) = &v3;
Controls__TControl__GetText(*(_DWORD *)(a1 + 768), &v7);
v9 = Sysutils__StrToFloat(v7);
Controls__TControl__GetText(*(_DWORD *)(v1 + 772), &v6);
v8 = Sysutils__StrToFloat(v6);
if ( v9 * v8 == 585858.0 ) Dialogs__ShowMessage(&str_crack_ok_[1]);
else
Dialogs__ShowMessage(&str_Username_or_pas[1]);
*MK_FP(__FS__, 0) = v3;
v5 = loc_4538F0;
return System____linkproc___LStrArrayClr(&v6, 2);
}
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能力值：
( LV2，RANK：10 )
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7 楼
看不懂啊！
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